document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=911054>Question 911054</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how could i solve this problem. suppose a small pump can empty out a swimming pool in 60 hours and a large pump can empty out a pool in 20 hours. working together how long would it take hem both to empty out the pool? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #552825 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=552825\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/a+1/b=1/x<BR>\n" );
document.write( "1/20+1/60=1/x<BR>\n" );
document.write( "60/1200+20/1200=1/x<BR>\n" );
document.write( "80/1200=1/x<BR>\n" );
document.write( "x=1200/80<BR>\n" );
document.write( "x=15 hours working together<BR>\n" );
document.write( "check<BR>\n" );
document.write( "x/a+x/b=1<BR>\n" );
document.write( "x/20+x/60=1<BR>\n" );
document.write( "15/20+15/60=1<BR>\n" );
document.write( "0.75+0.25=1<BR>\n" );
document.write( "1=1<BR>\n" );
document.write( "ok<BR>\n" );
document.write( "codewt<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );