document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=911012>Question 911012</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The formula for the perimeter P of a rectangle is P = 2l + 2w where l is the length and w is the width.  Solve the formula for l and write the reason for each step.  Then find the length of a rectangular lawn whose perimeter is 55 meters and whose width is 11 meters.   Drawing a picture would be helpful here.  <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #552807 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39618)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=552807\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Drawing a picture would be helpful, as you say.  Using better choices for variables is also a good idea, and in fact very important when using keyboard, computer input and characters.  \r<BR>\n" );
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document.write( "Your perimeter definition equation LOOKS like, the left member, P is equal to the right member described as the quantity twenty-one plus the term two times w.  \r<BR>\n" );
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document.write( "Use UPPER CASE L instead of the lower case L.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28P=2L%2B2w%29 ALIGN=MIDDLE  ALT=\"highlight_green%28P=2L%2B2w%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "Much easier to read.\r<BR>\n" );
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document.write( "The drawing you want is difficult to code, but maybe a description will help you to make a drawing on paper:<BR>\n" );
document.write( "Draw a rectangle.  One pair of opposite sides is 11 meters, and you should label their lengths as such.  The other pair of opposite sides are each L.  Label them.\r<BR>\n" );
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document.write( "You want to know L, but only are given P=55 and w=11.  You will see how the data corresponds to your drawing.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=55=2L%2B2%2A11 ALIGN=MIDDLE  ALT=\"55=2L%2B2%2A11\"   DISABLED_style= \"max-width:90%; height:auto;\" >, according to formula of perimeter and what the given values are.  Solve for L.<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2L%2B22=55 ALIGN=MIDDLE  ALT=\"2L%2B22=55\"   DISABLED_style= \"max-width:90%; height:auto;\" >, combined steps of simple computation and symmetric property of equality;<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2L=55-22 ALIGN=MIDDLE  ALT=\"2L=55-22\"   DISABLED_style= \"max-width:90%; height:auto;\" >, equivalent to addition property of equality, using additive inverse of 22;<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2L=33 ALIGN=MIDDLE  ALT=\"2L=33\"   DISABLED_style= \"max-width:90%; height:auto;\" >, simple computation;<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28L=33%2F2%29 ALIGN=MIDDLE  ALT=\"highlight%28L=33%2F2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, Multiplicative Inverse property  </SPAN>\n" );
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