document.write( "Question 911006: Tony invested in two bank accounts, the first with 5% annual interest and the second with 8% annual interest. For the one with 8%, he deposited $1500 more than the one with 5%. After a year his interest was $510. How much did Tony deposit on each account originally? \n" ); document.write( "
Algebra.Com's Answer #552805 by richwmiller(17219)\"\" \"About 
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We don't know the total invested.
\n" ); document.write( "We know the difference in the two accounts.
\n" ); document.write( "We know that the interest for the two accounts is $510
\n" ); document.write( "0.08*x+0.05*y=510
\n" ); document.write( "We know that the account at 8% has $1500 more.
\n" ); document.write( "x=1500+y
\n" ); document.write( "We substitute for x
\n" ); document.write( "0.08*(1500+y)+0.05*y=510
\n" ); document.write( "We multiply out
\n" ); document.write( "120+0.08y+0.05*y=510
\n" ); document.write( "We combine like terms.
\n" ); document.write( "0.13*y=390
\n" ); document.write( "Isolate y
\n" ); document.write( "y=$3000 at 5%
\n" ); document.write( "x=1500+y
\n" ); document.write( "Calculate x
\n" ); document.write( "x=$4500 at 8%
\n" ); document.write( "Now,we know the total invested is: 7500
\n" ); document.write( "Total invested $4500+$3000=$7500
\n" ); document.write( "We check
\n" ); document.write( "0.08*4500+0.05*3000=510
\n" ); document.write( "360+150=510
\n" ); document.write( "510=510
\n" ); document.write( "Since this statement is TRUE and neither x nor y is negative all is well.
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