document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=910745>Question 910745</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Landon can climb a certain hill at a rate that is 3.5 mph slower than his rate coming down the hill. If it take him 4 hours to climb the hill and 135 minutes to come down the hill. What is his rate coming down?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #552791 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=552791\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x*136/60=d,<BR>\n" );
document.write( "(x-3.5)*3=d<BR>\n" );
document.write( "x*136/60=(x-3.5)*3<BR>\n" );
document.write( "x*136/60=3x-10.5<BR>\n" );
document.write( "x*136/6=30x-105<BR>\n" );
document.write( "x*136=180x-630<BR>\n" );
document.write( "630=44x<BR>\n" );
document.write( "315=22x<BR>\n" );
document.write( "315/22=x<BR>\n" );
document.write( "x=14.32  mph downhill<BR>\n" );
document.write( "x-3.5=10.82 mph  uphill\r<BR>\n" );
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