document.write( "Question 77061: can you help me solve this problem\r
\n" ); document.write( "\n" ); document.write( "12 5
\n" ); document.write( " +  = 1
\n" ); document.write( "3x-2 x+4
\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #55279 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
:
\n" ); document.write( "\"12%2F%28%283x-2%29%29\" + \"5%2F%28%28x%2B4%29%29\" = 1
\n" ); document.write( ":
\n" ); document.write( "Multiply equation by (3x-2)(x+4) to get rid of the denominators, you then have:
\n" ); document.write( "12(x+4) + 5(3x-2) = (3x-2)(x+4)
\n" ); document.write( ":
\n" ); document.write( "12x + 48 + 15x - 10 = 3x^2 + 10x - 8
\n" ); document.write( ":
\n" ); document.write( "27x + 38 = 3x^2 + 10x - 8
\n" ); document.write( ":
\n" ); document.write( "0 = 3x^2 + 10x - 27x - 8 - 38
\n" ); document.write( ":
\n" ); document.write( "A quadratic equation:
\n" ); document.write( "3x^2 - 17x - 46 = 0
\n" ); document.write( ":
\n" ); document.write( "Factors to:
\n" ); document.write( "(3x-23)(x+2) = 0
\n" ); document.write( ":
\n" ); document.write( "3x = 23
\n" ); document.write( "x = 23/3
\n" ); document.write( "and
\n" ); document.write( "x = -2
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution using -2:
\n" ); document.write( "\"12%2F%28%283%28-2%29-2%29%29\" + \"5%2F%28%28-2%2B4%29%29\" = 1
\n" ); document.write( "\"12%2F%28%28-8%29%29\" + \"5%2F%28%282%29%29\" = 1
\n" ); document.write( "-1.5 + 2.5 = 1, proves our solution of -2,
\n" ); document.write( ":
\n" ); document.write( "I checked the x = 23/3 solution, using decimals on a calc. Anyway, did the
\n" ); document.write( "method make sense to you? \n" ); document.write( "
\n" );