document.write( "Question 910909: Barneys money earned $204 in interest after 1 year. He invested some of is money in an account earning 6% simple interest and $450 more than that account earning 5% simple interest. Find the amount Barney invested in each account. \n" ); document.write( "
Algebra.Com's Answer #552755 by richwmiller(17219)\"\" \"About 
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This plan has more at 5%\r
\n" ); document.write( "\n" ); document.write( "We don't know the total invested.
\n" ); document.write( "We know the difference in the two accounts.
\n" ); document.write( "We know that the interest for the two accounts is $204
\n" ); document.write( "0.05*x+0.06*y=204
\n" ); document.write( "We know that the account at 5% has $450 more.
\n" ); document.write( "x=450+y
\n" ); document.write( "We substitute for x
\n" ); document.write( "0.05*(450+y)+0.06*y=204
\n" ); document.write( "We multiply out
\n" ); document.write( "22.5+0.05y+0.06*y=204
\n" ); document.write( "We combine like terms.
\n" ); document.write( "0.11*y=181.5
\n" ); document.write( "Isolate y
\n" ); document.write( "y=$1650 at 6%
\n" ); document.write( "x=450+y
\n" ); document.write( "Calculate x
\n" ); document.write( "x=$2100 at 5%
\n" ); document.write( "Now,we know the total invested is: 3750
\n" ); document.write( "Total invested $2100+$1650=$3750
\n" ); document.write( "We check
\n" ); document.write( "0.05*2100+0.06*1650=204
\n" ); document.write( "105+99=204
\n" ); document.write( "204=204
\n" ); document.write( "Since this statement is TRUE and neither x nor y is negative all is well.
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