document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=910902>Question 910902</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two complementary angles are (9x-1) and (3x+7) degrees. Find their measures. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #552753 by </B><A HREF=/tutors/aboutme.mpl?userid=LinnW><B>LinnW(1048)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LinnW><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=LinnW><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=552753\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One of the angles is (9x-1)<BR>\n" );
document.write( "the other is (3x+7)\r<BR>\n" );
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document.write( "(9x-1) + (3x+7) = 90<BR>\n" );
document.write( "12x + 6 = 90<BR>\n" );
document.write( "add -6 to each side<BR>\n" );
document.write( "12x = 84<BR>\n" );
document.write( "divide each side by 12<BR>\n" );
document.write( "x = 7<BR>\n" );
document.write( "So the angle that is (9x-1) = (9(7)-1) = 63 - 1 = 62 degrees.<BR>\n" );
document.write( "Since the angles are complementary the other angle is 90 - 62 = 28 degrees.\r<BR>\n" );
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