document.write( "Question 910765: Hi,\r
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document.write( "I had listed the following problem awhile back. I was hoping for a quick response.\r
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document.write( "Which of the following expressions is equivalent to\r
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document.write( " 1 - tan^2x/tanx + 1\r
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document.write( "a)1 - tanx
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document.write( "b)cosx/1 - sinx
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document.write( "c)sec^2x/1 + sinx
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document.write( "d)1/sinxcosx \n" );
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Algebra.Com's Answer #552650 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Which of the following expressions is equivalent to \n" ); document.write( "(1 - tan^2x)/(tanx + 1) \n" ); document.write( "--- \n" ); document.write( "Factor the numerator to get: \n" ); document.write( "[(1-tan(x)(1+tan(x)]/[1+tan(x)] \n" ); document.write( "Cancel the common factor to get: \n" ); document.write( "= 1-tan(x) \n" ); document.write( "============= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------- \n" ); document.write( "a)1 - tanx \n" ); document.write( " b)cosx/1 - sinx \n" ); document.write( " c)sec^2x/1 + sinx \n" ); document.write( " d)1/sinxcosx \n" ); document.write( " |