document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=910746>Question 910746</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My question:Among coffee drinkers, men drank a mean of 3.2 cups per day with a standard deviation of 0.8 cups assume the # cups is normal distribution. <BR>\n" );
document.write( "a. What proportion drank 2 cups or more?<BR>\n" );
document.write( "b. What proportion drank no more than 4 cups per day? <BR>\n" );
document.write( "c. If 5% of coffee drinkers are considered heavy coffee drinkers what is the minimum number of cups consumed by a heavy coffee drinker?<BR>\n" );
document.write( "d.If a sample of 20 men is selected what is the probability that the mean number of cups per day is greater than 3? <BR>\n" );
document.write( "I am working on this problem and want to make sure I am on the right track. Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #552635 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=552635\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> mean = 3.2, sd = .8<BR>\n" );
document.write( "a) P(x &#8805; 2) = 1 - normalcdf(2, 100, 3.2,.8)....  100 a placehoder <BR>\n" );
document.write( "b) )(x &#8804; 4) = normalcdf(-100, 4, 3.2,.8)<BR>\n" );
document.write( "c) .8invNorm(.95) + 3.5 =X, number of cups consumed by a heavy coffee drinker<BR>\n" );
document.write( "d) s = .8/sqrt(20)<BR>\n" );
document.write( "P(x>3) = 1 - normalcdf(-100,3,3.2,s) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );