document.write( "Question 77060: can you help me understand how to find the vertex, the line of symmetry, and range with this problem\r
\n" ); document.write( "\n" ); document.write( "for the graph of the function f(x)=-x^2+6x-8\r
\n" ); document.write( "\n" ); document.write( "a. find the vertex\r
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Algebra.Com's Answer #55263 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
a)\r
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Solved by pluggable solver: Completing the Square to Get a Quadratic into Vertex Form

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\n" ); document.write( " \"y=1+x%5E2-6+x%2B8\" Start with the given equation
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\n" ); document.write( " \"y-8=1+x%5E2-6+x\" Subtract \"8\" from both sides
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\n" ); document.write( " \"y-8=1%28x%5E2-6x%29\" Factor out the leading coefficient \"1\"
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\n" ); document.write( " Take half of the x coefficient \"-6\" to get \"-3\" (ie \"%281%2F2%29%28-6%29=-3\").
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\n" ); document.write( " Now square \"-3\" to get \"9\" (ie \"%28-3%29%5E2=%28-3%29%28-3%29=9\")
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\n" ); document.write( " \"y-8=1%28x%5E2-6x%2B9-9%29\" Now add and subtract this value inside the parenthesis. Doing both the addition and subtraction of \"9\" does not change the equation
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\n" ); document.write( " \"y-8=1%28%28x-3%29%5E2-9%29\" Now factor \"x%5E2-6x%2B9\" to get \"%28x-3%29%5E2\"
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\n" ); document.write( " \"y-8=1%28x-3%29%5E2-1%289%29\" Distribute
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\n" ); document.write( " \"y-8=1%28x-3%29%5E2-9\" Multiply
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\n" ); document.write( " \"y=1%28x-3%29%5E2-9%2B8\" Now add \"8\" to both sides to isolate y
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\n" ); document.write( " \"y=1%28x-3%29%5E2-1\" Combine like terms
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\n" ); document.write( " Now the quadratic is in vertex form \"y=a%28x-h%29%5E2%2Bk\" where \"a=1\", \"h=3\", and \"k=-1\". Remember (h,k) is the vertex and \"a\" is the stretch/compression factor.
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\n" ); document.write( " Check:
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\n" ); document.write( " Notice if we graph the original equation \"y=1x%5E2-6x%2B8\" we get:
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\n" ); document.write( " \"graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C1x%5E2-6x%2B8%29\" Graph of \"y=1x%5E2-6x%2B8\". Notice how the vertex is (\"3\",\"-1\").
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\n" ); document.write( " Notice if we graph the final equation \"y=1%28x-3%29%5E2-1\" we get:
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\n" ); document.write( " \"graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C1%28x-3%29%5E2-1%29\" Graph of \"y=1%28x-3%29%5E2-1\". Notice how the vertex is also (\"3\",\"-1\").
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\n" ); document.write( " So if these two equations were graphed on the same coordinate plane, one would overlap another perfectly. So this visually verifies our answer.
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\n" ); document.write( "\n" ); document.write( "So if we multiply everything by -1 we get\r
\n" ); document.write( "\n" ); document.write( "\"y=-%28x-3%29%5E2%2B1\"\r
\n" ); document.write( "\n" ); document.write( "So the vertex is (3,1)\r
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\n" ); document.write( "The line of symmetry will go through the vertex so the equation is
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\n" ); document.write( "The range is any value y can be, so by our graph we can see the range is
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\n" ); document.write( "\n" ); document.write( "Here's our graph\r
\n" ); document.write( "\n" ); document.write( "\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+-x%5E2%2B6x-8%29+\" graph of \"y=-%28x-3%29%5E2%2B1\"
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