document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=910719>Question 910719</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A train takes 7 hours to travel from Station A to Station B. If its speed is increased by 10km/h. It will take 1 hour less to complete the journey. Find the distance between the two stations. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #552627 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=552627\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let speed of train be x<BR>\n" );
document.write( "let distance be y\r<BR>\n" );
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document.write( "time taken = y/x=7\r<BR>\n" );
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document.write( "speed increased by 10 km/h\r<BR>\n" );
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document.write( "(x+10)\r<BR>\n" );
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document.write( "time = y/(x+10)\r<BR>\n" );
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document.write( "y/x - y/(x+10) =1\r<BR>\n" );
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document.write( "7-y/(x+10)=1\r<BR>\n" );
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document.write( "y/(x+10)= 6\r<BR>\n" );
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document.write( "y=6x+60\r<BR>\n" );
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document.write( "but y=7x\r<BR>\n" );
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document.write( "7x=6x+60\r<BR>\n" );
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document.write( "x=60 distance between two stations<BR>\n" );
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