document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=910705>Question 910705</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of smallest square that can circumscribe a circle of area 616 sq. centimeter is? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #552618 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=552618\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Draw the description and you can determin that two times the radius is the side length of the square.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2Ar%5E2=616 ALIGN=MIDDLE  ALT=\"pi%2Ar%5E2=616\"   DISABLED_style= \"max-width:90%; height:auto;\" >, so the area of the square is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282r%29%282r%29 ALIGN=MIDDLE  ALT=\"%282r%29%282r%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >. </SPAN>\n" );
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