document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=910687>Question 910687</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3 feet more than 4 times its width and its width is 50 feet. A) Find the Area of the rectangle. B) Find the perimeter. C) Draw this rectangle on a coordinate plane and write the 4 ordered pairs of the vertices of the rectangle (be sure to label axis and use appropriate units of measure. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #552599 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=552599\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P = 2L + 2W<BR>\n" );
document.write( "L = 4W + 3<BR>\n" );
document.write( "W = 50<BR>\n" );
document.write( "If the width is 50, then the length is (4*50)+3, or 203<BR>\n" );
document.write( "Area = Length * width<BR>\n" );
document.write( "Area = 203 * 50 = 10,150<BR>\n" );
document.write( "Perimeter = 2(203) + 2(50) = 406 + 100 = 506<BR>\n" );
document.write( "You'll have to draw it yourself as I don't have that capability </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );