document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=910588>Question 910588</A>: <I><SPAN STYLE=\"word-break: break-all;\"> PLease explain your steps as I can understand how to work the problem.\r<BR>\n" );
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document.write( "\"and\" compound inequality-1 &#8804; 3 + 2x < 11 <BR>\n" );
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document.write( "\"or\" compound inequality  1 – x &#8805; -3 or 5x – 1 > 19 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #552558 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=552558\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> work the problem. <BR>\n" );
document.write( "\"and\" compound inequality<BR>\n" );
document.write( "-1 &#8804; 3 + 2x < 11<BR>\n" );
document.write( "Subtract 3 along the line to get:<BR>\n" );
document.write( "-4 <= 2x < 8<BR>\n" );
document.write( "Divide by 2 along the line to get:<BR>\n" );
document.write( "-2 <= x < 4<BR>\n" );
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document.write( "\"or\" compound inequality <BR>\n" );
document.write( "1 – x &#8805; -3 or 5x – 1 > 19<BR>\n" );
document.write( "-x >= -4 or 5x > 20<BR>\n" );
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document.write( "Note Dividing by a negative reverses the inequality::<BR>\n" );
document.write( "x <= 4 or x > 5<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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