document.write( "Question 910464: How many gallons of 70% antifreeze should be mixed with 10 gallons of 30% antifreeze to obtain a 45% antifreeze mixture?\r
\n" ); document.write( "\n" ); document.write( "Here's what I have
\n" ); document.write( "(0.30)(10gal)+(0.70)(x)=(0.45)(10+x)
\n" ); document.write( "After I solve this I get 6 gallons but when I check the solution I don't get 45% so this cannot be the right way to solve this problem. Please help.
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Algebra.Com's Answer #552545 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
We have 10 gal of 30% antifreeze
\n" ); document.write( "We want to add some 70% antifreeze to make 45% antifreeze
\n" ); document.write( "0.7*x+0.3*10=0.45(10+x)
\n" ); document.write( "0.7*x+3=4.5+0.45x
\n" ); document.write( "0.7x-0.45x=4.5-3
\n" ); document.write( "0.25x=1.5
\n" ); document.write( "x=6 gal at 70% (4.2) is added to 10 gal at 30%(3) to make 45% of 16 gal(7.2)
\n" ); document.write( "check
\n" ); document.write( "Remember it is 45% of 16 gallons that is .45*16 which is 7.2
\n" ); document.write( "0.7*6+0.3*10=0.45(10+6)
\n" ); document.write( "4.2+3=0.45(16)
\n" ); document.write( "7.2=7.2
\n" ); document.write( "ok
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