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Let Collin's current age = x
\n" ); document.write( "Let Christy's current age = y\r
\n" ); document.write( "\n" ); document.write( "Collin is 66 years older than Christy\r
\n" ); document.write( "\n" ); document.write( "This means that if we add 66 years to christy's age the total would be Collin's age. This translates algebraically to:
\n" ); document.write( "y + 60 = x\r
\n" ); document.write( "\n" ); document.write( "In 8 years he will be 3 times her age.
\n" ); document.write( "In 8 years means that Collin will be x + 8 years old and Christy will be y + 8 years old. and it says that his age then will be 3 times her age which traslates to:\r
\n" ); document.write( "\n" ); document.write( "(x + 8) = 3 * (y + 8)
\n" ); document.write( "simplifying this we get
\n" ); document.write( "x + 8 = 3y + 24
\n" ); document.write( "x = 3y + 16\r
\n" ); document.write( "\n" ); document.write( "Now we have 2 equations:
\n" ); document.write( "1)x = y + 60
\n" ); document.write( "2)x = 3y + 16
\n" ); document.write( "If we subtract (1) - (2) we get:\r
\n" ); document.write( "\n" ); document.write( "x - x = (y + 60) - (3y + 16)
\n" ); document.write( "0 = y + 60 - 3y - 16
\n" ); document.write( "0 = -2y + 44
\n" ); document.write( "y = 22 which is Christy's age
\n" ); document.write( "substitute this value of y in equation 1 or 2 (I will substitute it in 1)
\n" ); document.write( "x = y + 60
\n" ); document.write( "x = 22 + 60
\n" ); document.write( "x = 88
\n" ); document.write( "Therefore Collin's current age is 88 years old \n" ); document.write( "