document.write( "Question 910385: 4x=y^2 how do i determine if this equation defines y as a function of x?
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Algebra.Com's Answer #552446 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"4x=y%5E2\" does not define \"y\" as a function of \"x\", because some value(s) of \"x\" have more than one \"y\". \r
\n" ); document.write( "\n" ); document.write( "In general,
\n" ); document.write( "\"4x=y%5E2\" =>\"y=sqrt%284x%29\" or \"y=-sqrt%284x%29\" \r
\n" ); document.write( "\n" ); document.write( "=>\"+y=2sqrt%28x%29+\" or \"y=-2sqrt%28x%29\" \r
\n" ); document.write( "\n" ); document.write( "So, all the values of \"x\" larger than \"+0+\" would have two \"y\" values.\r
\n" ); document.write( "\n" ); document.write( "For example, \"x=16\" would be paired with \"y=2%2A4=8+and+%7B%7B%7By=-8\"\r
\n" ); document.write( "\n" ); document.write( "A function cannot assign more than one \"y+\"to any \"x\" value.\r
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