document.write( "Question 910315: A boat can travel 60 km/h in calm water. The boat travels 200 km against the current and then returns to the location where it started. If the trip takes 10 total hours, what is the speed of the current?\r
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document.write( "I started with t = dr to r = t/d
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document.write( "(1/60) x 10 = 10/600
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document.write( "10/200 = 10/600
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document.write( "cross multiply = 6000/2000=3
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document.write( "I don't know if 3 would be the answer or if I have to do more, or if its the answer I don't know if its the right answer. \n" );
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Algebra.Com's Answer #552428 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! r*t=d \n" ); document.write( "200/(60-c)+200/(60+c)=10/1 \n" ); document.write( "Multiply thru by 1*(60-c)(60+c) \n" ); document.write( "200*1*(60+c)+200*1(60-c)=10(c^2-3600) \n" ); document.write( "200*60+200*c+200*60-200*c=10*c^2-10*3600 \n" ); document.write( "12000+200*c+12000-200*c=10*c^2-36000 \n" ); document.write( "0=10*c^2-36000+(24000)+(0)*c \n" ); document.write( "10*c^2+-12000=0 \n" ); document.write( "10*c^2+-12000=0 \n" ); document.write( "c=34.641\r \n" ); document.write( "\n" ); document.write( "
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