document.write( "Question 910337: An airplane makes a trip in 3.2 hours flying against the wind. The same airplane makes the trip in 3 hours flying with the wind. If the wind is moving at 7 mph, what is the speed of the plane? Please show how you solved the problem as well. Thanks! \n" ); document.write( "
Algebra.Com's Answer #552415 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
Use rate(r) * time(t) = distance (d)
\n" ); document.write( "we are given t1 = 3.2 hours against the wind,
\n" ); document.write( "t2 = 3 hours with the wind and rw of the wind is 7 mph
\n" ); document.write( "the distance traveled d is the same for against the wind and with the wind
\n" ); document.write( "so we can set our equations = to each other
\n" ); document.write( "let r be the speed of the plane, then
\n" ); document.write( "(r-7) * 3.2 = (r+7) * 3
\n" ); document.write( "3.2r - 22.4 = 3r + 21
\n" ); document.write( "subtract 3r from both sides of =
\n" ); document.write( ".2r -22.4 = 21
\n" ); document.write( "add 22.4 to both sides of =
\n" ); document.write( ".2r = 43.4
\n" ); document.write( "r = 217 mph
\n" ); document.write( "the speed of the plane is 217 mph
\n" ); document.write( "check the answer in our equation
\n" ); document.write( "(217-7) * 3.2 = (217+7) * 3
\n" ); document.write( "672 = 672
\n" ); document.write( "our answer checks out ok \n" ); document.write( "
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