document.write( "Question 910337: An airplane makes a trip in 3.2 hours flying against the wind. The same airplane makes the trip in 3 hours flying with the wind. If the wind is moving at 7 mph, what is the speed of the plane? Please show how you solved the problem as well. Thanks! \n" ); document.write( "
Algebra.Com's Answer #552412 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! r*t=d \n" ); document.write( "with the wind \n" ); document.write( "(r+7)*3=d \n" ); document.write( "3*r+21=d \n" ); document.write( "against the wind \n" ); document.write( "(r-7)*3.2=d \n" ); document.write( "3.2*r-7*3.2=d \n" ); document.write( "3.2*r-22.4=d\r \n" ); document.write( "\n" ); document.write( "3.2*r-22.4=3*r+21 \n" ); document.write( "0.2r=43.4/0.2 \n" ); document.write( "r=217.0 mph rate plane \n" ); document.write( "distance=224.0*3=672.0 \n" ); document.write( "distance=210.0*3.2=672.0 \n" ); document.write( "check \n" ); document.write( "(217.0+7)*3= (217.0-7)*3.2 \n" ); document.write( "224.0*3=210.0*3.2 \n" ); document.write( "672.0=672.0 \n" ); document.write( "ok \n" ); document.write( " \n" ); document.write( " |