document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=910319>Question 910319</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the system<BR>\n" );
document.write( "x+2y=0<BR>\n" );
document.write( "3x-y=3\r<BR>\n" );
document.write( "\n" );
document.write( "This is what I did, but I am unsure if it is correct so far:<BR>\n" );
document.write( "x+2y=0<BR>\n" );
document.write( " -2y -2y<BR>\n" );
document.write( "x=-2y\r<BR>\n" );
document.write( "\n" );
document.write( "3(-2y)-y=3<BR>\n" );
document.write( "-6y-y=3<BR>\n" );
document.write( "-7y=3<BR>\n" );
document.write( "y=3/-7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #552409 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=552409\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We are given:<BR>\n" );
document.write( "x+2y=0<BR>\n" );
document.write( "3x-y=3 <BR>\n" );
document.write( "use second equation and solve for y<BR>\n" );
document.write( "add y to both sides of =, then subtract<BR>\n" );
document.write( "3 from both sides of =<BR>\n" );
document.write( "y = 3x-3<BR>\n" );
document.write( "substitute for y in first equation<BR>\n" );
document.write( "x + 2*(3x-3) = 0<BR>\n" );
document.write( "x + 6x - 6 = 0<BR>\n" );
document.write( "7x = 6<BR>\n" );
document.write( "x = 6/7<BR>\n" );
document.write( "now substitute for x in second equation<BR>\n" );
document.write( "3*(6/7) - y = 3<BR>\n" );
document.write( "18/7 - y = 3<BR>\n" );
document.write( "add y to both sides of = and subtract 21/7 (3) <BR>\n" );
document.write( "from both sides of =<BR>\n" );
document.write( "y = -3/7<BR>\n" );
document.write( "solution set is x = 6/7 and y = -3/7<BR>\n" );
document.write( "now check the answers<BR>\n" );
document.write( "substitute in first equation<BR>\n" );
document.write( "x+2y=0<BR>\n" );
document.write( "6/7 + 2*(-3/7) = 0<BR>\n" );
document.write( "6/7 -6/7 = 0<BR>\n" );
document.write( "0 = 0<BR>\n" );
document.write( "substitute in second equation<BR>\n" );
document.write( "3x-y=3<BR>\n" );
document.write( "3*(6/7) - (-3/7) = 3<BR>\n" );
document.write( "18/7 + 3/7 = 3<BR>\n" );
document.write( "21/7 = 3<BR>\n" );
document.write( "3 = 3<BR>\n" );
document.write( "our answers for x and y check   :-)<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );