document.write( "Question 910137: 3. Ted has $6.80 in quarters and dimes. The number of dimes is 3 times the number of quarters. Which system of equations can be used to find q, the number of quarters, and d, the number of dimes, that Ted has?
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Algebra.Com's Answer #552285 by Edwin McCravy(20081) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "Avoid decimals by thinking only in cents (pennies)\r\n" );
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\n" ); document.write( "3. Ted has $6.80 in quarters and dimes.
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document.write( "That's 680 pennies!\r\n" );
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document.write( "25q + 10d = 680\r\n" );
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\n" ); document.write( "The number of dimes is 3 times the number of quarters.
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document.write( "d = 3q\r\n" );
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\n" ); document.write( "Which system of equations can be used to find q, the number of quarters,
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document.write( "This system:\r\n" );
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document.write( "Trouble is, there is no way there could be any solution.\r\n" );
document.write( "12 quarters and 3 times as many dimes, which is 36 dimes, comes \r\n" );
document.write( "to only 660 ($6.60) <-- we're 20 cents short!\r\n" );
document.write( "And then 13 quarters and 3 times as many dimes or 39 dimes comes \r\n" );
document.write( "to 715 ($7.15)\r\n" );
document.write( "That's way over $6.80.  So we can't have 3 times as many dimes as\r\n" );
document.write( "quarters and have $6.80.    \r\n" );
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document.write( "The closest you could come is 12 quarters and 38 dimes\r\n" );
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document.write( "[ 12*25 + 38*10 = 300 + 380 = 680 ($6.80)\r\n" );
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document.write( "Your problem is botched.\r\n" );
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document.write( "Maybe it was supposed to be:\r\n" );
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document.write( "The number of quarters is 3 times the number of dimes.\r\n" );
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document.write( "Then you could have 24 quarters and 8 dimes because \r\n" );
document.write( "8*3=24 and 24*25+8*10 = 600+80 = 680 ($6.80)\r\n" );
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document.write( "Edwin

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