document.write( "Question 910167: How many gallons of 25% alcohol solution and 40% alcohol solution must be mixed to get 9 gallons of 30% alcohol solution?
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document.write( "Here's what I tried which has to be wrong...\r
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document.write( "25x+40y=30
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document.write( ".40+25(9-x)=30(9) ??? stumped and confused from hours of this.
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document.write( "Thank you ! \n" );
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Algebra.Com's Answer #552262 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! How many gallons of 25% alcohol solution and 40% alcohol solution must be mixed to get 9 gallons of 30% alcohol solution? \n" ); document.write( "*** \n" ); document.write( "let x=amt of 25% solution to mix \n" ); document.write( "9-x=amt of 40% solution to mix \n" ); document.write( ".. \n" ); document.write( "25%x+40%(9-x)=30%*9 \n" ); document.write( ".25x+3.6-.40x=2.7 \n" ); document.write( ".15x=0.90 \n" ); document.write( "x=6 \n" ); document.write( "9-x=3 \n" ); document.write( "amt of 25% solution to mix=6 gal \n" ); document.write( "amt of 40% solution to mix=3 gal \n" ); document.write( " |