document.write( "Question 910167: How many gallons of 25% alcohol solution and 40% alcohol solution must be mixed to get 9 gallons of 30% alcohol solution?
\n" ); document.write( "Here's what I tried which has to be wrong...\r
\n" ); document.write( "\n" ); document.write( "25x+40y=30
\n" ); document.write( ".40+25(9-x)=30(9) ??? stumped and confused from hours of this.
\n" ); document.write( "Thank you !
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Algebra.Com's Answer #552262 by lwsshak3(11628)\"\" \"About 
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How many gallons of 25% alcohol solution and 40% alcohol solution must be mixed to get 9 gallons of 30% alcohol solution?
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\n" ); document.write( "let x=amt of 25% solution to mix
\n" ); document.write( "9-x=amt of 40% solution to mix
\n" ); document.write( "..
\n" ); document.write( "25%x+40%(9-x)=30%*9
\n" ); document.write( ".25x+3.6-.40x=2.7
\n" ); document.write( ".15x=0.90
\n" ); document.write( "x=6
\n" ); document.write( "9-x=3
\n" ); document.write( "amt of 25% solution to mix=6 gal
\n" ); document.write( "amt of 40% solution to mix=3 gal
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