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document.write( "A rainwater collection tank is nearly full at a level of 120 in. The water will be used at a rate that lowers the level 6 in. per day. Which equation can be used to determine the time it will take (in days) to lower the level to 3 in.?\r
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Algebra.Com's Answer #55223 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! From the problem you know that the water level needs to drop from 120 inches deep to 3 inches \n" ); document.write( "deep. Therefore, the total amount of this drop is 120 - 3 inches. \n" ); document.write( ". \n" ); document.write( "Each day the water drops 6 inches. So if you multiply 6 times the number of days (D) you will \n" ); document.write( "get the total drop. Set these two total drops equal. In equation form it becomes: \n" ); document.write( ". \n" ); document.write( "6*D = 120 - 3 \n" ); document.write( ". \n" ); document.write( "Subtract the two numbers on the right side. When you do, you get that the amount of drop \n" ); document.write( "in the tank is 117 inches. Substitute this amount into the equation, and the equation \n" ); document.write( "becomes: \n" ); document.write( ". \n" ); document.write( "6*D = 117 inches \n" ); document.write( ". \n" ); document.write( "But we want to solve for D, the number of days that it takes for the level in the tank \n" ); document.write( "to be down to 3 inches. Do this by dividing both sides of the equation by 6, the multiplier \n" ); document.write( "of D. When you do, the equation is reduced to: \n" ); document.write( ". \n" ); document.write( "D = 117/6 = 19 + 3/6 = 19 + 1/2 = 19.5 days \n" ); document.write( ". \n" ); document.write( "In 19 and a half days the water will drop from 120 inches deep to 3 inches deep if the \n" ); document.write( "water level drops 6 inches a day. \n" ); document.write( ". \n" ); document.write( "Hope this helps you to understand the problem and how to set up and solve the equation.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |