document.write( "Question 77048This question is from textbook Glencoe Algebra 1
\n" ); document.write( ": \"5s-2s%5E2=0\" \n" ); document.write( "
Algebra.Com's Answer #55222 by chitra(359)\"\" \"About 
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The given expression is: \r
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\n" ); document.write( "\n" ); document.write( "\"+5s+-+2s%5E2+=+0+\" \r
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\n" ); document.write( "\n" ); document.write( "Since, the term \"s\" is present in both the terms, we can take it as a common factor. \r
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\n" ); document.write( "\n" ); document.write( "\"+s%285+-+2s%29+=+0+\" \r
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\n" ); document.write( "\n" ); document.write( "==> s = 0 or (5 - 2s) = 0 \r
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\n" ); document.write( "\n" ); document.write( "==> s = 0 or 5 = 2s \r
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\n" ); document.write( "\n" ); document.write( "==> s = 0 or s = \"5%2F2\" \r
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\n" ); document.write( "\n" ); document.write( "Hence, the solution.
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