document.write( "Question 77049This question is from textbook Glencoe Algebra 1
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Algebra.Com's Answer #55220 by bucky(2189) ![]() You can put this solution on YOUR website! \n" ); document.write( ". \n" ); document.write( "Notice that both terms on the left side contain the common factor n. Factor it out to \n" ); document.write( "get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Next notice that the expression within the parentheses is in the form of the difference \n" ); document.write( "of two squares. This is a common form that can be factored according to the following \n" ); document.write( "rule: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Applying this rule to \n" ); document.write( "into our first factor changes it to: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "This equation will be true if any of the three factors on the left side equal zero. Therefore, \n" ); document.write( "set each of the factors equal to zero and solve for the corresponding value of n, and the \n" ); document.write( "resulting three values of n will make the equation correct. \n" ); document.write( ". \n" ); document.write( "First, let \n" ); document.write( "that will cause the original equation of \n" ); document.write( ". \n" ); document.write( "Next, let \n" ); document.write( "equation is \n" ); document.write( "the original equation of \n" ); document.write( ". \n" ); document.write( "Finally, let \n" ); document.write( "equation is \n" ); document.write( "of \n" ); document.write( ". \n" ); document.write( "So the solutions to the original problem are n = 0, n = -9, and n= +9. \n" ); document.write( ". \n" ); document.write( "Hope this helps and shows you a way that you can solve for equations that can be factored.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |