document.write( "Question 909861: The function f is a fifth-degree polynomial with
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document.write( "the x-intercepts (-1, 0), (3, 0) and (5, 0)
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document.write( "y-intercept (0, 15) and
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document.write( "f (x) ≥ 0 for x ≤ 5.
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document.write( "How would I go about graphing something like this?\r
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document.write( "Thank you \n" );
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Algebra.Com's Answer #552149 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! we have f(x) = (x+1)(x-3)(x-5)g(x) for some second degree polynomial g(x) \n" ); document.write( "To determine g(x): \n" ); document.write( "We need f(x) ≥ 0 for x ≤ 5. \n" ); document.write( "==> (x + 1)(x - 3)(x - 5)g(x) ≥ 0 for x ≤ 5. \n" ); document.write( "Since we need g(x) to be quadratic, we can take g(x) = A(x + 1)(x - 3) for some constant A and \n" ); document.write( "Now, we have f(x) = A(x + 1)^2 (x - 3)^2 (x - 5) for some A. \n" ); document.write( "we use f(0) = A(1)^2 (-3)^2 (-5) = 15 \n" ); document.write( "15 = A*(1)*9*(-5) \n" ); document.write( "15 = -45A \n" ); document.write( "A = -1/3 \n" ); document.write( "therefore \n" ); document.write( "f(x) = (-1/3)(x + 1)^2 (x - 3)^2 (x - 5) \n" ); document.write( "this function can be graphed when multiplied out \n" ); document.write( " \n" ); document.write( " |