document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=909925>Question 909925</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A truck enters a highway driving 60 mph. A car enters the highway at the same place 13 minutes later and drives 66 mph in same direction. From the time the car enters the highway, how long will it take the car to pass the truck </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #552122 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=552122\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Gaining speed 66 -60= 6 mph<BR>\n" );
document.write( "Headstart 60*0.21666667 =13.0 miles<BR>\n" );
document.write( "Time to catch up 13.0/6=2 1/6 hours= 2 hours 10 minutes<BR>\n" );
document.write( "Algebraic solution<BR>\n" );
document.write( "60(t+0.21666667)=66t<BR>\n" );
document.write( "60t+13.0=66t<BR>\n" );
document.write( "13.0=66t-60t<BR>\n" );
document.write( "13.0=6t<BR>\n" );
document.write( "t=13.0/6=2 1/6 hours= 2 hours 10 minutes<BR>\n" );
document.write( "Distance to meeting 2.16666667*66=143 miles<BR>\n" );
document.write( "code drt1<BR>\n" );
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