document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=77038>Question 77038</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find an equation of a line passing through the points (3,3) and (-1,8) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #55212 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=55212\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> FIRST WE FIND THE SLOPE (Y2-Y1)/(X2-X1)<BR>\n" );
document.write( "(8-3)/(-1-3)=5/-4=-5/4<BR>\n" );
document.write( "NOW WE SUBSTITUTE ONE SET OF (X,Y) VALUES & SOLVE FOR THE Y INTERCEPT(b)<BR>\n" );
document.write( "3=-5/4*3+b<BR>\n" );
document.write( "3=-15/4+b<BR>\n" );
document.write( "b=3+15/4<BR>\n" );
document.write( "b=(12+15)/4<BR>\n" );
document.write( "b=27/4<BR>\n" );
document.write( "THUS THE EQUATION IS<BR>\n" );
document.write( "Y=-5/4X+27/4<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+-5x%2F4+%2B27%2F4%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+-5x%2F4+%2B27%2F4%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = -5x/4 +27/4).  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );