document.write( "Question 909916: Lisa traveled 1040 mi at a certain speed. If the speed had been 13 mph faster, the trip could have been in 4 hr. less time. Find the speed. \n" ); document.write( "
Algebra.Com's Answer #552117 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "\"1040%2Fr+-+1040%2F%28r%2B13%29+=+4\" |Multiplying thru by r(r+13) so as all denominators = 1
\n" ); document.write( "1040(r+13) - 1040r = 4r^2 + 52r
\n" ); document.write( "4r^2 +52r - 13(1040) = 0
\n" ); document.write( "r^2 + 13r - 13(260) = 0
\n" ); document.write( "r^2 + 13r - 3380 = 0 (Tossing out the negative solution for unit measure)
\n" ); document.write( "r = 52mph. 65mph \"52%2B13\" to save 4hrs
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B13x%2B-3380+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%2813%29%5E2-4%2A1%2A-3380=13689\".
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\n" ); document.write( " Discriminant d=13689 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-13%2B-sqrt%28+13689+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%2813%29%2Bsqrt%28+13689+%29%29%2F2%5C1+=+52\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%2813%29-sqrt%28+13689+%29%29%2F2%5C1+=+-65\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B13x%2B-3380\" can be factored:
\n" ); document.write( " \"1x%5E2%2B13x%2B-3380+=+1%28x-52%29%2A%28x--65%29\"
\n" ); document.write( " Again, the answer is: 52, -65.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B13%2Ax%2B-3380+%29\"
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