document.write( "Question 909916: Lisa traveled 1040 mi at a certain speed. If the speed had been 13 mph faster, the trip could have been in 4 hr. less time. Find the speed. \n" ); document.write( "
Algebra.Com's Answer #552117 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! Set Up \n" ); document.write( " \n" ); document.write( "1040(r+13) - 1040r = 4r^2 + 52r \n" ); document.write( "4r^2 +52r - 13(1040) = 0 \n" ); document.write( "r^2 + 13r - 13(260) = 0 \n" ); document.write( "r^2 + 13r - 3380 = 0 (Tossing out the negative solution for unit measure) \n" ); document.write( "r = 52mph. 65mph \n" ); document.write( "
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