document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=76959>Question 76959</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the system by substitution.<BR>\n" );
document.write( "	 x + 3y = –8<BR>\n" );
document.write( "	5x + 2y = 12<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #55210 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=55210\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X+3Y=-8, X=-3Y-8 NOW SUBSTITUTE (-3Y-8) FOR X & SOLVE FOR Y IN THE SECOND EQUATION.<BR>\n" );
document.write( "5(-3Y-8)+2Y=12<BR>\n" );
document.write( "-15Y-40+2Y=12<BR>\n" );
document.write( "-13Y=12+40<BR>\n" );
document.write( "-13Y=52<BR>\n" );
document.write( "Y=52/-13<BR>\n" );
document.write( "Y=-4 ANSWER.<BR>\n" );
document.write( "X+3*-4=-8<BR>\n" );
document.write( "X-12=-8<BR>\n" );
document.write( "X=-8+12<BR>\n" );
document.write( "X=4 ANSWER. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );