document.write( "Question 909873: A ball is thrown upward with an initial velocity of 48 feet per second from a height of 864 feet. Its height h in feet after t seconds is given by h(t) =-16t^2+48t+864 after how long will the ball reach the ground. \n" ); document.write( "
Algebra.Com's Answer #552084 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! h(t) =-16t^2+48t+864 \n" ); document.write( "0 = -16t^2+48t+864 \n" ); document.write( "0 = -16(x-3/2)^2 + 36 + 864 \n" ); document.write( "16(x-3/2)^2 = 900 \n" ); document.write( "x = 3/2 + 15/2= 9sec \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |