document.write( "Question 909780: After walking a distance of 6 miles at a certain rate, a man decided to increase his rate per hour by 1 mile and walked 5 miles farther. Had he walked the entire distance of 11 miles at his former rate, his time would have been 15 minutes longer. Find his former rate. \n" ); document.write( "
Algebra.Com's Answer #552028 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! After walking a distance of 6 miles at a certain rate, a man decided to increase his rate per hour by 1 mile and walked 5 miles farther. Had he walked the entire distance of 11 miles at his former rate, his time would have been 15 minutes longer. Find his former rate. \n" ); document.write( "*** \n" ); document.write( "let x=former rate \n" ); document.write( "x+1=increased rate \n" ); document.write( "15 min=1/4 hr \n" ); document.write( "travel time=distance/rate \n" ); document.write( ".. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "lcd:x(x+1) \n" ); document.write( "5x+5-5x=(x^2+x)/4 \n" ); document.write( "20x+20-20x=x^2+x \n" ); document.write( "x^2+x-20=0 \n" ); document.write( "(x+5)(x-4)=0 \n" ); document.write( "x=4 \n" ); document.write( "x+1=5 \n" ); document.write( "former rate=4 mph \n" ); document.write( " |