document.write( "Question 909782: A person plans to invest three times as much in a Dreyfus Premier Worldwide Growth R account at 4.5% interest as in an Oppenheimer Global Opportunities Y account at 14.9% annual interest. How much should the person invest in each account to earn a total of $426 in one year? \n" ); document.write( "

Algebra.Com's Answer #552027 by richwmiller(17219) $\"\"$ $\"About$

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We know that the interest for the two accounts is $426
\n" ); document.write( "0.045*x+0.149*y=426
\n" ); document.write( "We know that the account at 4.5% has 3 times the amount at 14.9%
\n" ); document.write( "We substitute for x
\n" ); document.write( "0.045*(3*y)+0.149*y=426
\n" ); document.write( "We multiply out
\n" ); document.write( "(0.135+0.149)*y=426
\n" ); document.write( "We combine like terms.
\n" ); document.write( "0.284*y=426
\n" ); document.write( "Isolate y
\n" ); document.write( "y= 1500.00
\n" ); document.write( "y=$ 1500.00 at 14.9%
\n" ); document.write( "Calculate x
\n" ); document.write( "x=3*y
\n" ); document.write( "x=$ 4500.00 at 4.5%
\n" ); document.write( "Your total for x is $ 4500.00
\n" ); document.write( "Your total for y is $ 1500.00
\n" ); document.write( "Your total for x and y is $ 6000.00
\n" ); document.write( "Total invested $ 4500.00 + $ 1500.00=$ 6000.00
\n" ); document.write( "We check
\n" ); document.write( "0.045* 4500.00+0.149* 1500.00=426
\n" ); document.write( " 202.50+ 223.50=426
\n" ); document.write( "426.0=426
\n" ); document.write( "Since this statement is TRUE and neither x nor y is negative then all is well.
\n" ); document.write( " \n" ); document.write( "

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