document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=909751>Question 909751</A>: <I><SPAN STYLE=\"word-break: break-all;\">   the length of a rectangle is 12 ft longer than twice the width. If the perimeter is 102 ft. find the length and width of the rectangle\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #552025 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=552025\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P = 2L + 2W<BR>\n" );
document.write( "P = 102<BR>\n" );
document.write( "L = 2W+12<BR>\n" );
document.write( "102 = 2(2W+12) + 2W<BR>\n" );
document.write( "102 = 4W + 24 + 2W<BR>\n" );
document.write( "102 = 6W + 24<BR>\n" );
document.write( "78 = 6W<BR>\n" );
document.write( "13 = W<BR>\n" );
document.write( "If the width is 13, then the length is twice that plus 12, or 38<BR>\n" );
document.write( "38 + 38 + 13 + 13 = 102 </SPAN>\n" );
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