document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=909418>Question 909418</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A train leaves a station and travels at 50 miles per hour. Fifteen minutes later, a second train leaves the same station and travels in the same direction on parallel tracks at 60 miles per hour. How long will it be before the second train overtake the first? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #551986 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=551986\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Gaining speed 60 -50= 10 mph<BR>\n" );
document.write( "Headstart 50*0.25 =12.5 miles<BR>\n" );
document.write( "Time to catch up 12.5/10=1.25 hours<BR>\n" );
document.write( "Algebraic solution<BR>\n" );
document.write( "50(t+0.25)=60t<BR>\n" );
document.write( "50t+12.5=60t<BR>\n" );
document.write( "12.5=60t-50t<BR>\n" );
document.write( "12.5=10t<BR>\n" );
document.write( "t=1.25  hours<BR>\n" );
document.write( "Distance to meeting 1.25*60=75 miles<BR>\n" );
document.write( "code drt1<BR>\n" );
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