document.write( "Question 909672: How do u do 1/5y=x+4 and y-x=8 in substitution and elimination \n" ); document.write( "

Algebra.Com's Answer #551983 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"1%2F5\"$ y = x + 4
\n" ); document.write( " and
\n" ); document.write( "y - x = 8
\n" ); document.write( "Arrange for substitution, add x to both sides
\n" ); document.write( "y = (x + 8)
\n" ); document.write( "Replace y in the 1st equation
\n" ); document.write( " $\"1%2F5\"$ (x+8) = x + 4
\n" ); document.write( "multiply both sides by 5
\n" ); document.write( "x + 8 = 5(x + 4)
\n" ); document.write( "x + 8 = 5x + 20
\n" ); document.write( "8 - 20 = 5x - x
\n" ); document.write( "-12 = 4x
\n" ); document.write( "x = -12/4
\n" ); document.write( "x = -3
\n" ); document.write( "Find y
\n" ); document.write( "y = -3 + 8
\n" ); document.write( "y = 5
\n" ); document.write( ":
\n" ); document.write( "Elimination,
\n" ); document.write( "y - x = 8
\n" ); document.write( " $\"1%2F5\"$ y - x = 4 (subtracted x from both sides)
\n" ); document.write( "----------subtraction eliminates x, find y
\n" ); document.write( " $\"4%2F5\"$ y + 0 = 4
\n" ); document.write( "multiply both sides by 5
\n" ); document.write( "4y = 5(4)
\n" ); document.write( "divide both sides by 4
\n" ); document.write( "y = 5
\n" ); document.write( ":
\n" ); document.write( "You can find x here\r
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