document.write( "Question 909671: 7. It takes a plane 3 hours to make a 900 mile trip with the wind. The return trip against the same wind takes 3 hours and 24 minutes. Find the speed of the plane in still air and the speed of the wind. \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #551980 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
r*t=d
\n" ); document.write( "with the wind
\n" ); document.write( "(r+w)*3=900
\n" ); document.write( "(r+w)=900/3
\n" ); document.write( "r+w=300
\n" ); document.write( "against the wind
\n" ); document.write( "(r-w)*3.4=900
\n" ); document.write( "(r-w)=900/3.4\r
\n" ); document.write( "\n" ); document.write( "r-w=264.705882
\n" ); document.write( "r+w=300
\n" ); document.write( "add
\n" ); document.write( "r+r=300+264.705882
\n" ); document.write( "2r=564.705882
\n" ); document.write( "r=282.352941 mph rate\r
\n" ); document.write( "\n" ); document.write( "282.352941-w=264.705882
\n" ); document.write( "w=282.352941-264.705882
\n" ); document.write( "w=17.6470588 mph wind
\n" ); document.write( "check
\n" ); document.write( "(282.352941+17.6470588)*3=900
\n" ); document.write( "300.0*3=900
\n" ); document.write( "900.0=900
\n" ); document.write( "ok
\n" ); document.write( "(r-w)*3.4=900
\n" ); document.write( "(282.352941-17.6470588)*3.4=900
\n" ); document.write( "264.705882*3.4=900
\n" ); document.write( "900.0=900
\n" ); document.write( "ok
\n" ); document.write( " \n" ); document.write( "
\n" );