document.write( "Question 909679: Flying with the wind, a plane flew 1500 mi in 5 h. Against the wind, the plane required 6 h to fly the same distance. Find the rate of the plane in calm air and the rate of the wind. \n" ); document.write( "
Algebra.Com's Answer #551977 by richwmiller(17219)\"\" \"About 
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r*t=d
\n" ); document.write( "with the wind
\n" ); document.write( "(r+w)*5=1500
\n" ); document.write( "(r+w)=1500/5
\n" ); document.write( "r+w=300
\n" ); document.write( "against the wind
\n" ); document.write( "(r-w)*6=1500
\n" ); document.write( "(r-w)=1500/6\r
\n" ); document.write( "\n" ); document.write( "r-w=250
\n" ); document.write( "r+w=300
\n" ); document.write( "add
\n" ); document.write( "r+r=300+250
\n" ); document.write( "2r=550
\n" ); document.write( "r=275 mph rate\r
\n" ); document.write( "\n" ); document.write( "275-w=250
\n" ); document.write( "w=275-250
\n" ); document.write( "w=25 mph wind
\n" ); document.write( "check
\n" ); document.write( "(275+25)*5=1500
\n" ); document.write( "300*5=1500
\n" ); document.write( "1500=1500
\n" ); document.write( "ok
\n" ); document.write( "(r-w)*6=1500
\n" ); document.write( "(275-25)*6=1500
\n" ); document.write( "250*6=1500
\n" ); document.write( "1500=1500
\n" ); document.write( "ok\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );