document.write( "Question 909677: Saul paid a bill of $4.60 with nickels, dimes, and quarters. The # of nickels was 3 less than the # of dimes. The #of dimes was 5 more than the # of quarters. How many coins of each type did he have? \n" ); document.write( "
Algebra.Com's Answer #551974 by JulietG(1812)![]() ![]() You can put this solution on YOUR website! # dimes = x \n" ); document.write( "# nickels = x-3 \n" ); document.write( "# quarters = x-5 \n" ); document.write( "15 dimes at .10 = 1.50 \n" ); document.write( "12 nickels at .05 = .60 \n" ); document.write( "10 quarters at .25 = 2.50 \n" ); document.write( "150 + 60 + 250 = 4.60 \n" ); document.write( "(I used estimation on the dimes and went from there) \n" ); document.write( " |