document.write( "Question 909677: Saul paid a bill of $4.60 with nickels, dimes, and quarters. The # of nickels was 3 less than the # of dimes. The #of dimes was 5 more than the # of quarters. How many coins of each type did he have? \n" ); document.write( "
Algebra.Com's Answer #551974 by JulietG(1812)\"\" \"About 
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# dimes = x
\n" ); document.write( "# nickels = x-3
\n" ); document.write( "# quarters = x-5
\n" ); document.write( "15 dimes at .10 = 1.50
\n" ); document.write( "12 nickels at .05 = .60
\n" ); document.write( "10 quarters at .25 = 2.50
\n" ); document.write( "150 + 60 + 250 = 4.60
\n" ); document.write( "(I used estimation on the dimes and went from there)
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