document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=909666>Question 909666</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Twice the length of a rectangle is 5 cm less than triple the width. If its perimeter is 50 cm, what is the area? Please show the representation ( ex. Let x be ________) and the working equation. I already know the answer but I got the answer using trial and error. Thank you very much! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #551968 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=551968\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P = 2L + 2W<BR>\n" );
document.write( "2L = 3W-5<BR>\n" );
document.write( "Substitute the value of 2L from the first equation into the second.<BR>\n" );
document.write( "P = 2L + 2W<BR>\n" );
document.write( "50 = (3W-5) + 2W<BR>\n" );
document.write( "50 = 5W - 5<BR>\n" );
document.write( "55 = 5W<BR>\n" );
document.write( "<b>11 = W</b><BR>\n" );
document.write( "If the width is 11, then two times the length is thrice that (33) minus 5, or 28/2 = <b>14</b><BR>\n" );
document.write( "14+14+11+11 = 50<BR>\n" );
document.write( " </SPAN>\n" );
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