document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=909627>Question 909627</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two squares of a combined area 68 cm². the side of one square is four times as long as a side of the other square. find the perimeter of each square </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #551961 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=551961\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Easiest way is to estimate the pairs.<BR>\n" );
document.write( "1,4<BR>\n" );
document.write( "2,8<BR>\n" );
document.write( "3,12<BR>\n" );
document.write( "Can't be 3,12 because the total are is 68 and 12 wipes that out.  Doubtful that it's 1,4 due to the 1.  Let's try 2,8<BR>\n" );
document.write( "2^2 + 8^2 = <BR>\n" );
document.write( "4 + 64 = 68<BR>\n" );
document.write( "That was pretty easy.  But you're looking for the perimeters.<BR>\n" );
document.write( "The perimeter of a square is 4s.<BR>\n" );
document.write( "First square's perimeter is 4(2) = 8<BR>\n" );
document.write( "Second square's perimeter is 4(8) = 32 </SPAN>\n" );
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