document.write( "Question 909628: The length of a rectangle is seven less than twice the width. If the perimeter is fourty six feet, what is the length and width? \n" ); document.write( "
Algebra.Com's Answer #551957 by JulietG(1812)\"\" \"About 
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P = 2L + 2W
\n" ); document.write( "L = 2W - 7
\n" ); document.write( "P = 46
\n" ); document.write( "46 = 2(2W-7) + 2W
\n" ); document.write( "46 = 4W-14 + 2W
\n" ); document.write( "46 = 6W - 14
\n" ); document.write( "60 = 6W
\n" ); document.write( "10 = W
\n" ); document.write( "If the width is 10, then the length is twice that minus 7, or 13
\n" ); document.write( "13+ 13+ 10 + 10 = 46
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