document.write( "Question 909392: A ship is anchored 9 miles from the nearest point of a straight beach. A man in the ship wishes to row to the shore and walk to a point on the beach 17 miles from the point directly opposite the ship. If he can row at the rate of 4 miles per hour and walk at the rate of 5 miles per hour, where ought he to land in order to reach his destination in 4 hour and 45 minutes? \n" ); document.write( "
Algebra.Com's Answer #551914 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A ship is anchored 9 miles from the nearest point of a straight beach.
\n" ); document.write( " A man in the ship wishes to row to the shore and walk to a point on the beach 17 miles from the point directly opposite the ship.
\n" ); document.write( " If he can row at the rate of 4 miles per hour and walk at the rate of 5 miles per hour, where ought he to land in order to reach his destination in 4 hour and 45 minutes?
\n" ); document.write( ":
\n" ); document.write( "A right triangle is formed by the ship, point on the shore directly opposite the ship, and a point on the landing point on the shore
\n" ); document.write( ":
\n" ); document.write( "Let x = dist between the opposite point and the landing point
\n" ); document.write( "The rowing path will be the hypotenuse of the triangle
\n" ); document.write( "(17-x) = dist from the landing point to the 17 mi point
\n" ); document.write( ":
\n" ); document.write( "Write a time equation; time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "Rowing time + walking time = 4.75 hrs
\n" ); document.write( "\"%28sqrt%28x%5E2%2B9%5E2%29%29%2F4\" + \"%28%2817-x%29%29%2F5\" = 4.75
\n" ); document.write( "multiply by 20 to clear the denominators, results:
\n" ); document.write( "\"5%28sqrt%28x%5E2%2B9%5E2%29%29\" + 4(17-x) = 20(4.75)
\n" ); document.write( ":
\n" ); document.write( "\"5%28sqrt%28x%5E2%2B9%5E2%29%29\" + 68 - 4x = 95
\n" ); document.write( ":
\n" ); document.write( " = 4x + 27
\n" ); document.write( "Square both sides,
\n" ); document.write( "25(x^2 + 81) = 16x^2 + 216x + 729
\n" ); document.write( "25x^2 + 2025 = 16x^2 + 216x + 729
\n" ); document.write( "Combine like terms on the left
\n" ); document.write( "25x^2 - 16x^2 - 216x + 2025 - 729 = 0
\n" ); document.write( "9x^2 - 216x + 1296 = 0
\n" ); document.write( "Simplify, divide by 9
\n" ); document.write( "x^2 - 24x + 144 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(x - 12)(x - 12) = 0
\n" ); document.write( "x = 12 miles from the opposite point to the landing point
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this out, find the rowing dist and walking dist
\n" ); document.write( "Rowing dist = \"sqrt%2812%5E2%2B9%5E2%29\" = 15 mi
\n" ); document.write( "Walking dist = 17 - 12 = 5 mi
\n" ); document.write( ":
\n" ); document.write( "Find the times
\n" ); document.write( "15/4 = 3.75 hrs rowing
\n" ); document.write( "5/5 = 1.0 hr walking
\n" ); document.write( "---------------------
\n" ); document.write( "total time 4.75 hrs
\n" ); document.write( "
\n" ); document.write( "
\n" );