document.write( "Question 909495: Please help, I have tried doing about twenty of these by myself and haven't gotten a single one right. I just don't understand at all.\r
\n" ); document.write( "\n" ); document.write( "The denominator of a fraction is three more than the numerator. If both numerator and denominator are decreased by four, the simplified result is 9/10. Find the original fraction.(do not simplify)
\n" ); document.write( "

Algebra.Com's Answer #551889 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let represent the numerator of the original fraction. Then the denominator of the original fraction must be , and\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "is a representation of the original fraction. Now, let's reduce each of the numerator and denominator by 4:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "and we are given that this new fraction is equivalent to so:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Cross-multiply:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Solve for , then calculate so that you can form the desired fraction.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Check your work. Take your answer, reduce each of the numerator and denominator by 4, and see if you have a fraction that reduces to \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "John
\n" ); document.write( "
\n" ); document.write( "My calculator said it, I believe it, that settles it
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" );