document.write( "Question 909495: Please help, I have tried doing about twenty of these by myself and haven't gotten a single one right. I just don't understand at all.\r
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document.write( "The denominator of a fraction is three more than the numerator. If both numerator and denominator are decreased by four, the simplified result is 9/10. Find the original fraction.(do not simplify) \n" );
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Algebra.Com's Answer #551889 by solver91311(24713) You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "is a representation of the original fraction. Now, let's reduce each of the numerator and denominator by 4:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "and we are given that this new fraction is equivalent to \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Cross-multiply:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve for \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check your work. Take your answer, reduce each of the numerator and denominator by 4, and see if you have a fraction that reduces to \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " |