document.write( "Question 909470: The total of two amounts of money is $600,000. The larger amount is invested at 8% and the smaller amount at 6%. The total annual income is $44,000. How much is each investment? \n" ); document.write( "

Algebra.Com's Answer #551887 by richwmiller(17219) $\"\"$ $\"About$

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Total amount of money invested: $600000
\n" ); document.write( "x+y=600000,
\n" ); document.write( "Total yearly interest for the two accounts is: $44000
\n" ); document.write( "0.08*x+0.06*y=44000
\n" ); document.write( "x=600000-y
\n" ); document.write( "Substitute for x
\n" ); document.write( "0.08*(600000-y)+0.06*y=44000
\n" ); document.write( "Multiply out
\n" ); document.write( "48000-0.08*y+0.06*y=44000
\n" ); document.write( "Combine like terms.
\n" ); document.write( "-0.02*y=-4000
\n" ); document.write( "Isolate y
\n" ); document.write( "y=$200000.00 at 6%
\n" ); document.write( "x=600000-y
\n" ); document.write( "Calculate x
\n" ); document.write( "x=$400000.00 at 8%
\n" ); document.write( "Check
\n" ); document.write( "0.08*400000+0.06*200000=44000
\n" ); document.write( "32000+12000=44000
\n" ); document.write( "44000=44000
\n" ); document.write( "If this statement is TRUE and neither x nor y is negative then all is well
\n" ); document.write( "code int1
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