document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=909495>Question 909495</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help, I have tried doing about twenty of these by myself and haven't gotten a single one right. I just don't understand at all.\r<BR>\n" );
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document.write( "The denominator of a fraction is three more than the numerator. If both numerator and denominator are decreased by four, the simplified result is 9/10. Find the original fraction.(do not simplify)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #551877 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=551877\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> n/n+3<BR>\n" );
document.write( "(n-4)/(n+3-4)=9/10<BR>\n" );
document.write( "9*(n+3-4)=10*(n-4)<BR>\n" );
document.write( "9n-9=10n-40\r<BR>\n" );
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document.write( "n=31<BR>\n" );
document.write( "31/34 original fraction<BR>\n" );
document.write( "31-4=27<BR>\n" );
document.write( "34-4=30<BR>\n" );
document.write( "27/30=9/10<BR>\n" );
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