document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=909468>Question 909468</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A part of a sum of money is invested at 5% and the other part which is three times as much as the first at 8%. The total annual interest earning is $58,000. How much is invested at each rate? show solution pls </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #551872 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=551872\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A part of a sum of money is invested at 5% and the other part which is three times as much as the first at 8%. The total annual interest earning is $58,000. How much is invested at each rate? show solution pls<BR>\n" );
document.write( "------------------------<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "interest + interest = interest<BR>\n" );
document.write( "0.05x + 0.08(3x) = 58000<BR>\n" );
document.write( "----<BR>\n" );
document.write( "5x + 24x = 5800000<BR>\n" );
document.write( "29x = 5800000<BR>\n" );
document.write( "x = $200,000 (amt. invested at 5%)<BR>\n" );
document.write( "3x = $600,000 (amt. invested at 8%)<BR>\n" );
document.write( "---------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );