document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=909460>Question 909460</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many kilos containing 6% butterfat must be added to 220 kilos of cream containing 22% butterfat to make a mixture containing 10% butterfat? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #551866 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=551866\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many kilos containing 6% butterfat must be added to 220 kilos of cream containing 22% butterfat to make a mixture containing 10% butterfat?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "fat + fat = fat<BR>\n" );
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document.write( "0.06x + 0.22*220 = 0.10(x+220)<BR>\n" );
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document.write( "6x + 22*220 = 10x + 10*220<BR>\n" );
document.write( "-4x = -12*220<BR>\n" );
document.write( "x = 3*220<BR>\n" );
document.write( "x = 660 kilos (amt of 6% needed)<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
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