document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=909362>Question 909362</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Thank you for helping me! There are three questions on my homework which I have tried and failed could you please help me with them.<BR>\n" );
document.write( "Question one is: Rectangle A has one side which is 6cm long and the other is (x+2)cm long. Rectangle B has sides of length (2x+1)cm and 3cm. If the perimeters are the same, calculate the value of x and hence, the lengths of the sides of the triangles.<BR>\n" );
document.write( "I have tried to work out this question, making x four but this does not work as it gives me sides of 6 and 6 on triangle A.<BR>\n" );
document.write( "My Second question is that: Rectangle X measures 7cm by (x+1)cm. Rectangle b has dimensions of (3x+6)cm and 4cm. The area of rectangle X is half the area of rectangle B. Calculate the lengths of the sides of the rectangles and their areas.             (Please reply as soon as possible, thanks) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #551837 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=551837\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> perimeter = 2L + 2W, where L = length and W = width.\r<BR>\n" );
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document.write( "In rectangle A this becomes 2*6 + 2*(x+2)<BR>\n" );
document.write( "in rectangle B, this becomes 2*3 + 2*(2x+1)\r<BR>\n" );
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document.write( "simplify each expression and you get:\r<BR>\n" );
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document.write( "perimeter of A = 16 + 2x<BR>\n" );
document.write( "perimeter of B = 8 + 4x\r<BR>\n" );
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document.write( "since the perimeters are equal, you get 16 + 2x = 8 + 4x\r<BR>\n" );
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document.write( "solve for x in this equation and you get x = 4\r<BR>\n" );
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document.write( "when x = 4, the perimeter of A is 24 and the perimeter of B is 24.\r<BR>\n" );
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document.write( "in your second problem, area of a rectantgle is equal to L*W, where L = length and W = width.\r<BR>\n" );
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document.write( "area of rectangle X is equal to 7 * (x+1)<BR>\n" );
document.write( "area of rectangle B is equal to 4 * (3x + 6)\r<BR>\n" );
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document.write( "the area of rectangle X is equal to 1/2 * the area of rectangle B.\r<BR>\n" );
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document.write( "You get:\r<BR>\n" );
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document.write( "7 * (x+1) = 1/2 * 4 * (3x + 6)\r<BR>\n" );
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document.write( "simplify to get 7x + 7 = 6x + 12\r<BR>\n" );
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document.write( "solve for x in this equation to get x = 5\r<BR>\n" );
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document.write( "when x = 5:\r<BR>\n" );
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document.write( "area of rectangle X is equal to 7 * (x+1) becomes 7 * 6 which becomes 42.<BR>\n" );
document.write( "area of rectangle B is equal to 4 * (3x + 6) becomes 4 * 21 which becomes 84.\r<BR>\n" );
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document.write( "since 42 is equal to 1/2 * 84, the equations confirm the solution of x = 5 as good.\r<BR>\n" );
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document.write( "i'm assuming you know how to simplify and how to solve equations so i didn't give you the details of how the results were obtained.\r<BR>\n" );
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document.write( "if you don't understand how i got the answers, then let me know and i'll guide you through it.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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